The two functional blocks
The circuit consists of two blocks. Block one is a simple power switch maneuvered by K1 and the other part is the inrush current limiter formed by relay K2 and R1.
The purpose of K1 is to relieve the power switch from the main current and lower the demands of this switch. You can use any switch capable of switching 2 A at 250 VAC (or 110 VAC if you have this AC voltage). If you of some reason don't want to use this feature, just put a wire in X3 and if you don't want a LED indication, put a wire in X4 also. If you do want a LED indication, this LED must be properly insulated because it is floating at main potential and is (may be) therefore lethal to touch. The original idea for the LED idea come from that I wanted to use a switch with built-in LED.
This design have I used now since 1989 in the QRO-amp. So the design is well proven. The C1, C2 design is used in time relays and manufactured in millions of copies. I have personal experience of this circuit. More than 10000 units are out and none of them have had any failure of the C1, C2 cap.
The power for the electronics is derived through a capacitor which acts like a "lossless resistor". This technique is possible to use if the wave shape of the mains is good enough (sinus with no harmonics). The size of the C1 and C2 is rather critical. If you are going to use 110-120 VAC the capacitance must be double, but this isn't tested yet, the exact value.
Trimming brightness of the LED
R2 is for trimming the brightness of the LED which may be located inside the mains switch. I personally like mains switches with LED's but unfortunately the are rather small, can't handle much current. K1 is used for unloading the switch. A 2 x 5 (8) A relay will last at least 10 years. My have lasted 20 years with a 600 VA transformer. R2 act also as protection for negative voltages across the LED.
Avoiding unpleasant surprises
R3-R5 are for avoiding unpleasant surprises, to discharge the C1 and C2. Three resistors is used to ensure resistance against transients. The total value should be between 220 kohms to 3 Mohms.
R6-R9 limit the max inrush current for C1 and C2. Four resistors are used simply because they are small and cheap.
B1 fullwave rectifies the voltage and is limited by the zener DZ1 when the normal load is small. The zener is hardly necessary since you always have a load in K1.
The C6 should not be too large. Larger capacitors reduces the supply voltage, not the other way around. This is because we have a capacitive voltage divider. C1, C2 and C6 forms a voltage divider.
D1 is for isolating the timing circuit and insure a short reset time.
The timing circuit
R11 and C4, C5 is the timing circuit. R12, R13 makes the time longer. T2 is simply a buffer since K2 consumes rather much current. You can use a small mosfet as T3, BS170 or similar but I have chosen here to only use common parts.
Only C4 gives a sufficient delay time for most situations but the time can be increased by mounting also C5. No harm to have both, but R1 may have to be changed due to extra power dissipation.
C3 is smoothing for the timing voltage and this capacitors should be as small as possible. R10 is a bleeder which discharges the whole timing circuit as fast as possible. The is one of the main features, fast reset time.
R1 limits the inrush current. 5 W is enough for at least 600 VA and rather much smoothing. My power supply has 600 VA and 88000 uF, 2 x 63 V, 4 x 22000 uF. Chosen value of R1 gives 3 A as max current. The holes in the pcb are extra large so it's possible to solder in wires and use an external resistor if you have need for it. The holes are 1.5 mm.
Other mains voltages
The pcb is not tested yet for 110-120 VAC but I'll expect that 2 x 0.68 uF (C1, C2) would be sufficient. The capacitor value is also dependent of the relays and their current consumption.
I have chosen here an Schrack relay which can handle 8 ampere but I consider Elesta SGR282 24 VDC as one of the best relays there is. It is also rated to 8 ampere. Note also that max switching current probably is very low most of the time because you don't switch off the amp at full power. With this assumption the relay will be able to handle more than 8 A as long it's not switched.